document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=632007>Question 632007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two hoses fill a pool in 2 hours. If only hose A is used, the pool is filled in 3 hours. How long would it take if only hose B is used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397955 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two hoses fill a pool in 2 hours. If only hose A is used, the pool is filled in 3 hours. How long would it take if only hose B is used?<BR>\n" );
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document.write( "Let x = time (hours) it takes for hose B alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2(1/3 + 1/x) = 1<BR>\n" );
document.write( "multiplying both sides by 3x:<BR>\n" );
document.write( "2(x+ 3) = 3x<BR>\n" );
document.write( "2x+ 6 = 3x<BR>\n" );
document.write( "6 hours = x<BR>\n" );
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document.write( "answer: 6 hours </SPAN>\n" );
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