document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58201>Question 58201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Michelle is eight years older than Adam.  Three years ago Michelle was twice as old as Adam was then.  How old is Michelle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39795 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let M = Michelle's present age.<BR>\n" );
document.write( "Let A = Adam's present age.\r<BR>\n" );
document.write( "\n" );
document.write( "M = A + 8  Michelle is 8 yrs older than Adam.<BR>\n" );
document.write( "M-3 = 2(A-3) 3 yrs ago, Michelle was twice Adam's age.  Solve this equation for A and substitute into the first equation, then solve for M.\r<BR>\n" );
document.write( "\n" );
document.write( "M-3 = 2A-6 Add 6 to both sides.<BR>\n" );
document.write( "M+3 = 2A Divide both sides by 2<BR>\n" );
document.write( "M/2+3/2 = A  Substitute this into the first equation and solve for M\r<BR>\n" );
document.write( "\n" );
document.write( "M = ((M/2)+3/2)+8 Multiply by 2 to clear the fractions.<BR>\n" );
document.write( "2M = (M+3) + 16  Simplify.<BR>\n" );
document.write( "M = 19\r<BR>\n" );
document.write( "\n" );
document.write( "Michelle's age is 19.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );