document.write( "Question 631910: Find the equation of the line perpendicular to 4x-5y=3 through (2,3).
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Algebra.Com's Answer #397948 by Maths68(1474)\"\" \"About 
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Given
\n" ); document.write( "Point (x, y)=(2,3)
\n" ); document.write( "Line:
\n" ); document.write( "4x-5y=3
\n" ); document.write( "-5y=-4x+3
\n" ); document.write( "-5y/-5=(-4x+3)/-5
\n" ); document.write( "y=-4x/-5-3/5
\n" ); document.write( "y=(4/5)x-3/5
\n" ); document.write( "Compare above equation with the equation of line slope-intercept form
\n" ); document.write( "y=mx+b\r
\n" ); document.write( "\n" ); document.write( "m=4/5 and b=-3/5
\n" ); document.write( "Slope of the given line m = 4/5 and y-intercept = b = -3/5\r
\n" ); document.write( "\n" ); document.write( "Since required line is perpendicular, the multiplication of the slopes of both lines result in (-1), therefore the slope of the required line will be (-5/4)
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\n" ); document.write( "Now we have a point (2,3) and slope (-5/4) of the required line we can easily find the required line put these values in the equation of slope-intercept form to find the y-intercept of the required line
\n" ); document.write( "y=mx+b
\n" ); document.write( "3=(-5/4)(2)+b
\n" ); document.write( "3=-10/4+b
\n" ); document.write( "3+10/4=b
\n" ); document.write( "(12+10)/4=b
\n" ); document.write( "22/4=b
\n" ); document.write( "11/2=b
\n" ); document.write( "b=11/2
\n" ); document.write( "y-intercept of the required line = b = 11/2 and slope = m = -5/4
\n" ); document.write( "Put the values of ‘m’ and ‘b’ in equation of the line slope-intercept form
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=(-5/4)x+11/2
\n" ); document.write( "Above equation is the required equation of the line in slope-intercept form.\r
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\n" ); document.write( "y=(4/5)x-3/5 (Given line)
\n" ); document.write( "y=(-5/4)x+11/2(Required line)\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C4x%2F5-3%2F5%2C-5x%2F4%2B11%2F2%29+\"
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