document.write( "Question 631939: At best buy Larry buys three CDs and three CDs for $108 from the sale rack. Kelly buys two CDs and one DVD from the same rack for $48. What is the price per CD and the price per DVD.? \n" ); document.write( "

Algebra.Com's Answer #397923 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = the cost of 1 CD
\n" ); document.write( "Let $\"+b+\"$ = the cost of 1 DVD
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+3a+%2B+3b+=+108+\"$
\n" ); document.write( "(2) $\"+2a+%2B+1b+=+48+\"$
\n" ); document.write( "Multiply both sides of (2) by $\"+3+\"$
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) $\"+6a+%2B+3b+=+144+\"$
\n" ); document.write( "(1) $\"+-3a+-+3b+=+-108+\"$
\n" ); document.write( " $\"+3a+=+36+\"$
\n" ); document.write( " $\"+a+=+12+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+2a+%2B+1b+=+48+\"$
\n" ); document.write( "(2) $\"+2%2A12+%2B+1b+=+48+\"$
\n" ); document.write( "(2) $\"+24+%2B+b+=+48+\"$
\n" ); document.write( "(2) $\"+b+=+24+\"$
\n" ); document.write( "The price per CD is $12 and
\n" ); document.write( "the price per DVD is $24
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+3%2A12+%2B+3%2A24+=+108+\"$
\n" ); document.write( "(1) $\"+36+%2B+72+=+108+\"$
\n" ); document.write( "(1) $\"+108+=+108+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+2%2A12+%2B+1%2A24+=+48+\"$
\n" ); document.write( "(2) $\"+24+%2B+24+=+48+\"$
\n" ); document.write( "OK \n" ); document.write( "

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