document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631918>Question 631918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a right triangle with legs measuring 7 and 24. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397904 by </B><A HREF=/tutors/aboutme.mpl?userid=benni1013><B>benni1013(206)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benni1013><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A couple of pretexts:<BR>\n" );
document.write( "1) Perimeter deals with the measure around the shape NOT inside the shape<BR>\n" );
document.write( "2) You need to use the pythagorean theorem (a^2+b^2=c^2). A and B are the legs. C is the hypotenuse, the long side.\r<BR>\n" );
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document.write( "First, what do we know.<BR>\n" );
document.write( "1) We know the legs of the triangle a and b equal 7 and 24.<BR>\n" );
document.write( "2) Start plugging into the Pythagorean theorem.\r<BR>\n" );
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document.write( "WORK:<BR>\n" );
document.write( "7^2+24^2=c^2>>49+576=c^2>>625=c^2>>25=c*<BR>\n" );
document.write( "*To undo a exponent use a square root and vice versa\r<BR>\n" );
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document.write( "With the hypotenuse found, add the three sides to find the perimeter\r<BR>\n" );
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document.write( "WORK:<BR>\n" );
document.write( "7+24+25=56 ?*\r<BR>\n" );
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document.write( "*For future benefit, ALWAYS label your solutions! </SPAN>\n" );
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