document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631814>Question 631814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?<BR>\n" );
document.write( "i only got as far as tan a = 3/4:2/3<BR>\n" );
document.write( "and cot b = 1/ (3/4:2/3)<BR>\n" );
document.write( "i am obviously lost please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397849 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "1st find the cos(a) and sin(b)<BR>\n" );
document.write( "cos = sqrt(1 - sin^2) - sqrt(1 - 9/16)<BR>\n" );
document.write( "cos(a) = sqrt(7)/4<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "find the sin(b) the same way.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "then it's tan = sin/cos, etc<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );