document.write( "Question 631794: 20(3+4x)-7(8-6x)=150 \n" ); document.write( "

Algebra.Com's Answer #397839 by jim_thompson5910(35256) $\"\"$ $\"About$

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$\"20%283%2B4x%29-7%288-6x%29=150\"$ Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " $\"60%2B80x-56%2B42x=150\"$ Distribute.\r
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\n" ); document.write( "\n" ); document.write( " $\"122x%2B4=150\"$ Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( " $\"122x=150-4\"$ Subtract $\"4\"$ from both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"122x=146\"$ Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=%28146%29%2F%28122%29\"$ Divide both sides by $\"122\"$ to isolate $\"x\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"x=73%2F61\"$ Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is $\"x=73%2F61\"$ \r
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