document.write( "Question 631805: Given that a parabola has a directrix of y=-3.25 and focus (0,-2.75), find the vertex.\r
\n" ); document.write( "\n" ); document.write( "then write an equation of the parabola\r
\n" ); document.write( "\n" ); document.write( "then graph the parabola\r
\n" ); document.write( "\n" ); document.write( "please show all work\r
\n" ); document.write( "\n" ); document.write( "Thank You
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Algebra.Com's Answer #397820 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \"y=a%28x-h%29%5E2+%2Bk\"
\n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry
\n" ); document.write( "The standard form is \"%28x+-h%29%5E2+=+4p%28y+-k%29\", where the focus is (h,k + p)
\n" ); document.write( "and length of the latus rectum
\n" ); document.write( "directrix of y= -3.25 and focus (0,-2.75),
\n" ); document.write( "y-value of Midpoint between directrix and focus is -6/2 = -3 , p = .25 and 4p = 1 V(0,-3)
\n" ); document.write( " \"++x%5E2+=+%28y%2B3%29\" or \"y+=+x%5E2+-+3+\"\r
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