document.write( "Question 631790: how do you find three consecutive odd positive integers such that 2 times the sum of all three is 9 less than the product of the first and second integers \n" ); document.write( "
Algebra.Com's Answer #397807 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "three consecutive odd positive integers \"highlight%28x%29\", \"highlight%28x+%2B+2%29\" , \"highlight%28x%2B4%29\"
\n" ); document.write( "2 times the sum of all three is 9 less than the product of the first and second integers
\n" ); document.write( " 2(3x + 6)=x(x+2)-9
\n" ); document.write( " 6x + 12 = x^2 + 2x-9
\n" ); document.write( " 0 = x^2-4x - 21
\n" ); document.write( " 0 = (x-7)(x+3) x = 7
\n" ); document.write( "The three consecutive odd positive integers are 7 , 9 , 11\r
\n" ); document.write( "\n" ); document.write( "and...
\n" ); document.write( " \"2%2A27+=+54+=+7%2A9++-+9\"
\n" ); document.write( " \n" ); document.write( "
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