document.write( "Question 631783: A farmer sold 50 apples and 20 oranges for a total of $30.00. The apples were 4/5 the price of the oranges. what is the price of each apple and each orange? Write a algebraic equation and solve. \n" ); document.write( "

Algebra.Com's Answer #397799 by 55305(86) $\"\"$ $\"About$

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First lets assume that the cost of an orange is x. That means that the cost of an apple is 4/5*x. So the cost of 50 apples and 20 oranges is 50*4/5*x+20x. Since the cost of 50 apples and 20 oranges is $30, lets set that equal to 30. So we get 50*4/5*x+20x=30, which simplifies to 40x+20x=30, and that simplified is 60x=30. and if we divide each side by 60, we get x=0.50. That means an orange costs $0.50, and an apple costs 4/5 of that price, or $0.40. \n" ); document.write( "

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