document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58181>Question 58181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know it says not linear equations but can someone please help me with this one? Thank You!\r<BR>\n" );
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document.write( "Thanks Again! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39779 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to solve we isolate y to solve for x\r<BR>\n" );
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document.write( "0.5x-0.3y=7<BR>\n" );
document.write( "move the x to the side<BR>\n" );
document.write( "-.3y=7-.5x<BR>\n" );
document.write( "0.3Y=-7+0.5X<BR>\n" );
document.write( "divide both sides to isolate y\r<BR>\n" );
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document.write( "Y=(-7/.3)+(0.5/0.3)X\r<BR>\n" );
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document.write( "now you substitute in the new equation for y in the second equation\r<BR>\n" );
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document.write( "0.3x-0.4((-7/.3)+(0.5/0.3)X)=2\r<BR>\n" );
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document.write( "expand the terms into the brackets and simplify the term\r<BR>\n" );
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document.write( "0.3X+(28/3)+-(2/3)x=2<BR>\n" );
document.write( "11/30X+(28/3)=2<BR>\n" );
document.write( "subtract (28/3) from each side<BR>\n" );
document.write( "11/30X=-22/3<BR>\n" );
document.write( "divide out 11/30 from each side to isolate x<BR>\n" );
document.write( "x=-20\r<BR>\n" );
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document.write( "now substitute x into the equation to find y\r<BR>\n" );
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document.write( "0.5(-20)-0.3y=7<BR>\n" );
document.write( "-10-.3Y=7<BR>\n" );
document.write( "add 10 to each side<BR>\n" );
document.write( "-.3Y=-3<BR>\n" );
document.write( "divide by .3<BR>\n" );
document.write( "y=10\r<BR>\n" );
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document.write( "so x is -20 and y is 10 </SPAN>\n" );
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