document.write( "Question 631701: A man made a deposit of $106. If the deposit consisted of 42 coins some are 1 dollar and the rest is 5 dollar.How many coins of each kind did he have ? \n" ); document.write( "
Algebra.Com's Answer #397762 by Theo(13342)\"\" \"About 
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x = number of 1 dollar bills
\n" ); document.write( "y = number of 5 dollar bills
\n" ); document.write( "x + y = 42 (total number of bills)
\n" ); document.write( "x + 5y = 106 (total money)
\n" ); document.write( "from the first equation, you can solve for x to get x = 42 - y
\n" ); document.write( "substitute for s in the second equation to get:
\n" ); document.write( "x + 5y = 106 becomes 42 - y + 5y = 106
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "42 + 4y = 106
\n" ); document.write( "subtract 42 from both sides of this equation to get:
\n" ); document.write( "4y = 106 - 42 which becomes 4y = 64
\n" ); document.write( "divide both sides of this equation by 4 to get y = 64/4 = 16
\n" ); document.write( "since x + y = 42, this means that x = 42 - 16 which is equal to 26.
\n" ); document.write( "you have x = 26 and y = 16
\n" ); document.write( "1 * x = 26 dollars
\n" ); document.write( "5 * y = 5 * 16 = 80 dollars
\n" ); document.write( "80 dollars plus 26 dollars is equal to 106 dollars
\n" ); document.write( "you're good.
\n" ); document.write( "x = 26 and y = 16 is your answer.\r
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