document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631657>Question 631657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylinder contains 50 liters of a 60% chemical solution.  How much of this solution should be drained off and replaced with a 40% solution to obtain a final strength of 46%?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397745 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397745\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cylinder contains 50 liters of a 60% chemical solution.  How much of this solution should be drained off and replaced with a 40% solution to obtain a final strength of 46%?<BR>\n" );
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document.write( "Let x = amount (liters) of 40% solution <BR>\n" );
document.write( "then<BR>\n" );
document.write( ".60(50-x) + .40x = .46(50)<BR>\n" );
document.write( "30-.60x + .40x = 23<BR>\n" );
document.write( "30-.20x = 23<BR>\n" );
document.write( "-.20x = -7<BR>\n" );
document.write( "x = -7/(-.20)<BR>\n" );
document.write( "x = 35 liters<BR>\n" );
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