document.write( "Question 631671: What is the center point of this graph and what is the radius? according to this equation :\r
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document.write( "4y^2 = 4(x+2)^2 +16 \n" );
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Algebra.Com's Answer #397739 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the center point of this graph and what is the radius? according to this equation : \n" ); document.write( "4y^2 = 4(x+2)^2 +16 \n" ); document.write( "4y^2 - 4(x+2)^2 =16 \n" ); document.write( "divide by 16 \n" ); document.write( "y^2/4 - (x+2)^2/4 =1 \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form:(y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center. \n" ); document.write( "center of given hyperbola: (0,-2) \n" ); document.write( "radius does not apply in this case \n" ); document.write( " \n" ); document.write( " |