document.write( "Question 631671: What is the center point of this graph and what is the radius? according to this equation :\r
\n" ); document.write( "\n" ); document.write( "4y^2 = 4(x+2)^2 +16
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Algebra.Com's Answer #397739 by lwsshak3(11628)\"\" \"About 
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What is the center point of this graph and what is the radius? according to this equation :
\n" ); document.write( "4y^2 = 4(x+2)^2 +16
\n" ); document.write( "4y^2 - 4(x+2)^2 =16
\n" ); document.write( "divide by 16
\n" ); document.write( "y^2/4 - (x+2)^2/4 =1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis.
\n" ); document.write( "Its standard form:(y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of center.
\n" ); document.write( "center of given hyperbola: (0,-2)
\n" ); document.write( "radius does not apply in this case
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