document.write( "Question 631675: A MAN IS 27 YEARS OLDER THAN HIS SON , AND IN 10 YEARS FROM NOW HE WILL BE TWICE AS OLD AS HIS SON . HOW OLD IS EACH NOW ?
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Algebra.Com's Answer #397738 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Man = m years old
\n" ); document.write( "Present age of Son = s years old\r
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\n" ); document.write( "\n" ); document.write( "Man is 27 years older than his son
\n" ); document.write( "m=s+27...........(1)\r
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\n" ); document.write( "\n" ); document.write( "In 10 years
\n" ); document.write( "Man will be = m+10 years old
\n" ); document.write( "Son will be = s+10 years old
\n" ); document.write( "Then
\n" ); document.write( "Man will be twice as old as his Son
\n" ); document.write( "m+10=2(s+10)
\n" ); document.write( "m+10=2s+20
\n" ); document.write( "m=2s+20-10
\n" ); document.write( "m=2s+10...............(2)
\n" ); document.write( "Substitute the value of m from (1) to (2)
\n" ); document.write( "s+27=2s+10
\n" ); document.write( "s-2s=10-27
\n" ); document.write( "-s=-17
\n" ); document.write( "Multiply by -1 both sides
\n" ); document.write( "s=17
\n" ); document.write( "Substitute the value of s in (1)
\n" ); document.write( "m=s+27
\n" ); document.write( "m=17+27
\n" ); document.write( "m=44\r
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\n" ); document.write( "\n" ); document.write( "Present age of Man = m = 44 years old
\n" ); document.write( "Present age of Son = s = 17 years old\r
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