document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631663>Question 631663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 80m.the length is decresed by 2m and width is increased by 2m.By doing this the area of a rectangle will be increased by 36 sq.m. What is the length and width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397733 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length be l & width be w\r<BR>\n" );
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document.write( "2(l+w)= 80 perimeter\r<BR>\n" );
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document.write( "l+w = 40 \r<BR>\n" );
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document.write( "new length = (l-2)<BR>\n" );
document.write( "new width = (w+2)\r<BR>\n" );
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document.write( "New area - old area = 36\r<BR>\n" );
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document.write( "(l-2)(w+2)-lw=36<BR>\n" );
document.write( "lw+2l-2w-4-lw=36<BR>\n" );
document.write( "2l-2w=40<BR>\n" );
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document.write( "l-w=20<BR>\n" );
document.write( "l+w=40\r<BR>\n" );
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document.write( "add both equations<BR>\n" );
document.write( "2l=60<BR>\n" );
document.write( "l=30<BR>\n" );
document.write( "so w=10\r<BR>\n" );
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document.write( "The dimensions of rectangle are 30 & 10 m\r<BR>\n" );
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document.write( " </SPAN>\n" );
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