document.write( "Question 631628: A person drives 390 miles on a stretch
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document.write( "of road. Half the distance is driven traveling 5
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document.write( "miles per hour below the speed limit, and half the
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document.write( "distance is driven traveling 5 miles per hour above
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document.write( "the speed limit. If the time spent traveling at the slower
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document.write( "speed exceeds the time spent traveling at the faster
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document.write( "speed by 24 minutes, find the speed limit. \n" );
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Algebra.Com's Answer #397715 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let the speed limit be x mph\r \n" ); document.write( "\n" ); document.write( "First half speed = (x-5) mph \n" ); document.write( "Second half speed = (x+5) mph\r \n" ); document.write( "\n" ); document.write( "Half distance = 390/2 = 195 miles\r \n" ); document.write( "\n" ); document.write( "24 minutes = 24/60 = 2/5 hours\r \n" ); document.write( "\n" ); document.write( "time = distance/speed\r \n" ); document.write( "\n" ); document.write( "First half time = 195/(x-5)\r \n" ); document.write( "\n" ); document.write( "Seond half time = 195/(x+5)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "LCD = 5(x+5)(x-5)\r \n" ); document.write( "\n" ); document.write( "Multiply equation by the LCD \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "975x+4875-975x+4875 = 2(x^2-25)\r \n" ); document.write( "\n" ); document.write( "9750 = 2x^2-50 \n" ); document.write( "2x^2= 9800 \n" ); document.write( "/2 \n" ); document.write( "x^2= 4900 \n" ); document.write( "take the square root \n" ); document.write( "x= 70 mph\r \n" ); document.write( "\n" ); document.write( "Speed limit is 70 mph\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |