document.write( "Question 631600: write an equation in slope-intercept form (y=mx+b) for the perpendicular bisector of the segment between (3,4) and (-2,5)...please show all steps \n" ); document.write( "
Algebra.Com's Answer #397705 by mananth(16946) You can put this solution on YOUR website! (3,4) and (-2,5) \n" ); document.write( "The equation for this line is to be determined. \n" ); document.write( "x1 y1 x2 y2 \n" ); document.write( "3 4 -2 5 \n" ); document.write( " \n" ); document.write( "slope m = (y2-y1)/(x2-x1) \n" ); document.write( "( 5 - 4 )/( -2 - 3 ) \n" ); document.write( "( 1 / -5 ) \n" ); document.write( "m= - 1/ 5 \n" ); document.write( " \n" ); document.write( "Find theco-ordinates of the mid point (3,4) and (-2,5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3-2)/2 = 0.5\r \n" ); document.write( "\n" ); document.write( "(4+5)/2 = 4.5\r \n" ); document.write( "\n" ); document.write( "The co-ordinates of the mid point are (0.5,4.5)\r \n" ); document.write( "\n" ); document.write( "Equation of line perpendicular to the line joining (3,4) and (-2,5)and passing through (0.5,4.5) \n" ); document.write( "Equation of line joining the points \n" ); document.write( "y = - 1/ 5 x + 23/5 \n" ); document.write( "Divide by 1 \n" ); document.write( " y = - 1/ 5 x + 23/5 \n" ); document.write( "Compare this equation with y=mx+b, \n" ); document.write( "m= slope & b= y intercept \n" ); document.write( "slope m = - 1/5 \n" ); document.write( " \n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal. \n" ); document.write( "Because m1*m2 =-1 \n" ); document.write( "The slope of the required line will be 5 \n" ); document.write( " \n" ); document.write( "m= 5 ,point ( 0.5 , 4.5 ) \n" ); document.write( "Find b by plugging the values of m & the point in \n" ); document.write( "y=mx+b \n" ); document.write( "4.5 = 5/ 2 + b \n" ); document.write( "b= 2 \n" ); document.write( "m= 5 \n" ); document.write( "The required equation is y=5x+2 \r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |