document.write( "Question 631327: A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour. At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
\n" ); document.write( "The car arrived to B, stayed there 2 hours and started driving back to A at the same speed. After a 1/4 of the way back the car met the bicycle.
\n" ); document.write( "What is the distance between A to B?
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Algebra.Com's Answer #397687 by ankor@dixie-net.com(22740)\"\" \"About 
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A bicycle rider left at 6 a.m. city A to city B at the speed of 15 km an hour.
\n" ); document.write( " At 8 a.m. a car left city A for city B at the speed of 75 km an hour.
\n" ); document.write( "The car arrived to B, stayed there 2 hours and started driving back to A at the
\n" ); document.write( " same speed.
\n" ); document.write( "After a 1/4 of the way back the car met the bicycle.
\n" ); document.write( "What is the distance between A to B?
\n" ); document.write( ":
\n" ); document.write( "Let d = distance from A to B
\n" ); document.write( "then when they met:
\n" ); document.write( ".75d = distance traveled by the bike
\n" ); document.write( "1.25d = distance traveled by the car
\n" ); document.write( ":
\n" ); document.write( "From the information given, we know the bike travel time was 4 hrs more than the car.
\n" ); document.write( "(The car left two hrs after the bike and stayed at B for 2 hrs}
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "Bike time - car time = 4 hrs
\n" ); document.write( "\"%28.75d%29%2F15\" - \"%281.25d%29%2F75\" = 4
\n" ); document.write( "multiply by 75
\n" ); document.write( "5(.75d) - 1.25d = 75(4)
\n" ); document.write( "3.75d - 1.25d = 300
\n" ); document.write( "2.50d = 300
\n" ); document.write( "d = 300/2.50
\n" ); document.write( "d = 120 km from A to B
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