document.write( "Question 631354: HELLO,
\n" ); document.write( "If anyone answer my questions i will be truly grateful
\n" ); document.write( "Find the square root of: 640.09
\n" ); document.write( "Find the square root of: 9682.56
\n" ); document.write( "

Algebra.Com's Answer #397661 by KMST(5396)\"\" \"About 
You can put this solution on YOUR website!
I assume that a pencil and paper calculation is required, because a calculator would give you the answer easily.
\n" ); document.write( "
\n" ); document.write( "If the square roots are going to be rational numbers, the way to go is:
\n" ); document.write( "\"sqrt%28640.09%29=sqrt%2864009%2F100%29=sqrt%2864009%29%2Fsqrt%28100%29=sqrt%2864009%29%2F10\" and
\n" ); document.write( "
\n" ); document.write( "If the square roots are going to be rational numbers, 64009 and 968256 must be perfect squares.
\n" ); document.write( "From there, I would try to factor the numbers in the square roots.
\n" ); document.write( "A complete prime factorization is not needed, but the idea is similar.
\n" ); document.write( "
\n" ); document.write( "64009 is not divisible by 2 (it is not even) or 3 (digits do not add to a multiple of 3).
\n" ); document.write( "It is not divisible by 5 (does not end in 0 or 5) or by 7 (I tried dividing).
\n" ); document.write( "It is divisible by 11, because the sums of alternate digits differ by 11:
\n" ); document.write( "(6+0+9)-(4+0)=15-4=11
\n" ); document.write( "If is is a perfect square, \"11%5E2\" will be a factor, so I can divide by 11 twice.
\n" ); document.write( "I did, and I got 64009/11=5819 and 5819/11=529.
\n" ); document.write( "The number 529 sounded familiar, as if I had known it as a perfect square.
\n" ); document.write( "Since 529 ends in 9, it must be the square of a number that ends in 3 or 7.
\n" ); document.write( "That number be smaller than 25, because \"25%5E2=625%3E529\" ,
\n" ); document.write( "but larger than 20 because \"20%5E2=400%3C529\"
\n" ); document.write( "I tried 23 and found that \"23%5E2=529\"
\n" ); document.write( "So \"64009=11%2A11%2A23%5E2=11%5E2%2A23%5E2=%2811%2A23%29%5E2=253%5E2\" and \"sqrt%2864009%29=253\"
\n" ); document.write( "So \"sqrt%28640.09%29=sqrt%2864009%29%2F10=253%2F10=25.3\"
\n" ); document.write( "
\n" ); document.write( "968256 is divisible by 2, and if it is a perfect square it must be divisible by \"2%5E2=4\".
\n" ); document.write( "So I divided by 4 once to get 968256/4=242064, and again to get 242064/4=60516,
\n" ); document.write( "and a third time to get 60516/4=15129, that is not divisible by 2 any more.
\n" ); document.write( "15129 is divisible by \"3%5E2=9\" and I divided 15129/9=1681.
\n" ); document.write( "If 1681 going to be a perfect square, it must be the square of a number that ends in 1 or 9, and is a bit larger than 40, because \"40%5E2=1600%3C1681\".
\n" ); document.write( "I tried 41 and found that \"41%5E2=1681\" so
\n" ); document.write( "41^2*9*4*4*4=41^2*3^2*64=41^2*3^2*8^2=(41*3*8)^2=984^2=968256 and \"sqrt%28968256%29=984\"
\n" ); document.write( "So \"sqrt%289682.56%29=sqrt%28968256%29%2F10=984%2F10=98.4\"
\n" ); document.write( "
\n" ); document.write( "There is a general way to find square roots, that even allows you to get approximate values for irrational squre roots. It can be worked into a procedure sort of like long division, which I was taught in school many, many years ago. I hope that is not what was expected from you in the era of smartphones and tablet computers.
\n" ); document.write( "
\n" );