document.write( "Question 631354: HELLO,
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document.write( "If anyone answer my questions i will be truly grateful
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document.write( "Find the square root of: 640.09
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document.write( "Find the square root of: 9682.56 \n" );
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Algebra.Com's Answer #397661 by KMST(5396) You can put this solution on YOUR website! I assume that a pencil and paper calculation is required, because a calculator would give you the answer easily. \n" ); document.write( " \n" ); document.write( "If the square roots are going to be rational numbers, the way to go is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If the square roots are going to be rational numbers, 64009 and 968256 must be perfect squares. \n" ); document.write( "From there, I would try to factor the numbers in the square roots. \n" ); document.write( "A complete prime factorization is not needed, but the idea is similar. \n" ); document.write( " \n" ); document.write( "64009 is not divisible by 2 (it is not even) or 3 (digits do not add to a multiple of 3). \n" ); document.write( "It is not divisible by 5 (does not end in 0 or 5) or by 7 (I tried dividing). \n" ); document.write( "It is divisible by 11, because the sums of alternate digits differ by 11: \n" ); document.write( "(6+0+9)-(4+0)=15-4=11 \n" ); document.write( "If is is a perfect square, \n" ); document.write( "I did, and I got 64009/11=5819 and 5819/11=529. \n" ); document.write( "The number 529 sounded familiar, as if I had known it as a perfect square. \n" ); document.write( "Since 529 ends in 9, it must be the square of a number that ends in 3 or 7. \n" ); document.write( "That number be smaller than 25, because \n" ); document.write( "but larger than 20 because \n" ); document.write( "I tried 23 and found that \n" ); document.write( "So \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "968256 is divisible by 2, and if it is a perfect square it must be divisible by \n" ); document.write( "So I divided by 4 once to get 968256/4=242064, and again to get 242064/4=60516, \n" ); document.write( "and a third time to get 60516/4=15129, that is not divisible by 2 any more. \n" ); document.write( "15129 is divisible by \n" ); document.write( "If 1681 going to be a perfect square, it must be the square of a number that ends in 1 or 9, and is a bit larger than 40, because \n" ); document.write( "I tried 41 and found that \n" ); document.write( "41^2*9*4*4*4=41^2*3^2*64=41^2*3^2*8^2=(41*3*8)^2=984^2=968256 and \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "There is a general way to find square roots, that even allows you to get approximate values for irrational squre roots. It can be worked into a procedure sort of like long division, which I was taught in school many, many years ago. I hope that is not what was expected from you in the era of smartphones and tablet computers. \n" ); document.write( " |