document.write( "Question 631467: completely factor the expression 4q^2+27r^4
\n" ); document.write( "a. 31q^2+27r^4
\n" ); document.write( "b. 27r^4(4q^2+1)
\n" ); document.write( "c. 4q(q+27r)
\n" ); document.write( "d. prime
\n" ); document.write( "If you could please explain I would really appreciate it
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Algebra.Com's Answer #397596 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
There are no common factors between the coefficients 4 and 27. There are also no common factors between the variables q^2 and r^4\r
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\n" ); document.write( "\n" ); document.write( "So the GCF is 1. This means that it's trivial to factor out the GCF (since we get the same thing really after we do)\r
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\n" ); document.write( "\n" ); document.write( "Also, this is a binomial. This means that only the difference of squares rule is used to factor, but we have a sum (and not a difference) of terms.\r
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\n" ); document.write( "\n" ); document.write( "So we can't use that method either.\r
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\n" ); document.write( "\n" ); document.write( "So this expression is prime since it can't be factored.\r
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\n" ); document.write( "\n" ); document.write( "Note: you can also go through the other options and rule them out. For example, choice C) is 4q(q+27r) which distributes to 4q^2 + 108rq, which is NOT the original expression. So choice C is out. You would do the same for the other answer choices.\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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