document.write( "Question 631371: what time after 4 o'clock will the hands of the contionously drive clock from a right angle? \n" ); document.write( "
Algebra.Com's Answer #397587 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
At exactly 4 o'clock, the big hand is on the 12
\n" ); document.write( "and the little hand is on the 4. They span 20
\n" ); document.write( "minutes out of 60, or 120 degrees out of 360 degrees
\n" ); document.write( "------------------
\n" ); document.write( "The minute hand will move at the rate of 360 degrees / hr
\n" ); document.write( "The hour hand will move at the rate of \"+5%2F60%29%2A360+=+30+\"
\n" ); document.write( "degrees / hr
\n" ); document.write( "------------------
\n" ); document.write( "I want the difference between them to be 90 degrees with
\n" ); document.write( "the difference starting out at 120 degrees
\n" ); document.write( "Let \"+a+\" = the angle between the hands
\n" ); document.write( "Let \"+t+\" = the time in hours for the angle between them
\n" ); document.write( "to equal 90 degrees
\n" ); document.write( "-------------------
\n" ); document.write( "\"+a+=+%28+120+%2B+30t+%29+-+%28+360t+%29+\"
\n" ); document.write( "\"+90+=+%28+120+%2B+30t+%29+-+%28+360t+%29+\"
\n" ); document.write( "\"+90+=+120+-+330t+\"
\n" ); document.write( "\"+330t+=+120+-+90+\"
\n" ); document.write( "\"+330t+=+30+\"
\n" ); document.write( "\"+t+=+1%2F11+\" hrs
\n" ); document.write( "\"+1%2F11%2A60+=+5+%2B+5%2F11+\" minutes
\n" ); document.write( "\"+5%2F11%2A60+=+27.27+\"
\n" ); document.write( "---------------
\n" ); document.write( "The hands will be 90 degrees apart at
\n" ); document.write( "4:05 and 27 sec
\n" ); document.write( "check:
\n" ); document.write( "\"+a+=+%28+120+%2B+30t+%29+-+%28+360t+%29+\"
\n" ); document.write( "\"+a+=+%28+120+%2B+30%2A%281%2F11%29+%29+-+%28+360%2A%281%2F11%29+%29+\"
\n" ); document.write( "\"+a+=+%28+120+%2B+2.7272+%29+-++%28+32.7272+%29+\"
\n" ); document.write( "\"+a+=+120+-+30+\"
\n" ); document.write( "\"+a+=+90+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );