document.write( "Question 631438: solve the following quadratic equaton for x
\n" ); document.write( "(2x+1)(x+3)=0
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Algebra.Com's Answer #397579 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "If (2x+1)(x+3)=0 ⇒
\n" ); document.write( " (2x+1)= 0
\n" ); document.write( "or
\n" ); document.write( " (x+3)=0
\n" ); document.write( " x = -1/2 or x = -3 \n" ); document.write( "
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