document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631317>Question 631317</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A person has invested $6000 . Part of the money is invested at 3% and the remaining amout at 4% . The annual income from the two investment is $225.How much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397521 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A person has invested $6000 . Part of the money is invested at 3% and the remaining amout at 4% . The annual income from the two investment is $225.How much is invested at each rate?<BR>\n" );
document.write( "ans:-<BR>\n" );
document.write( "say at 3% he invested $ x <BR>\n" );
document.write( "so at 4% $(6000-x)<BR>\n" );
document.write( "SO 3%X+4%(6000-X)=225<BR>\n" );
document.write( "or 3x+4*6000-4x=225*100=22500<BR>\n" );
document.write( "or 3x-4x=22500-24000=-1500<BR>\n" );
document.write( "or -x=-1500<BR>\n" );
document.write( "or x=1500 at 3%<BR>\n" );
document.write( "6000-1500=4500 at 4%ans<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );