document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631372>Question 631372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the 4th term of the geometric progression is -32 and the 7th term is 108,what is the 9th term? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397516 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the 4th term of the geometric progression is -32 and the 7th term is 108,what is the 9th term?<BR>\n" );
document.write( "ans:-<BR>\n" );
document.write( "let the 1st term of GP=a & common ratio=r<BR>\n" );
document.write( "then 4th term =ar^3= -32 .....eqn 1<BR>\n" );
document.write( "and  7th term =ar^6=108,......eqn 2<BR>\n" );
document.write( "dividing eqn 2 by eqn 1<BR>\n" );
document.write( "we get r^3=108/-32=-27/8......eqn 3<BR>\n" );
document.write( "or r=-3/2<BR>\n" );
document.write( "now  dividing eqn 1 by eqn 3 <BR>\n" );
document.write( "we will get a= 32*8/27<BR>\n" );
document.write( "the 9th term=ar^8= (32*8/27)(-3/2)^8=243 ans </SPAN>\n" );
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