document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631362>Question 631362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 5 less than 3 times a second number. Their sum is 43. Find the numbers.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397511 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 5 less than 3 times a second number. Their sum is 43. Find the numbers.<BR>\n" );
document.write( "ans:-<BR>\n" );
document.write( "let one no is x<BR>\n" );
document.write( "the other no is 3x-5<BR>\n" );
document.write( "as per question (APQ)x+3x-5=43<BR>\n" );
document.write( "or 4x=43+5=48<BR>\n" );
document.write( "or x=12<BR>\n" );
document.write( "so the nos are 12 & (43-12=)31 ans </SPAN>\n" );
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