document.write( "Question 58109: To meet the governments specifications, an alloy must be 65% aluminum. How many pounds each of a 70% aluminum alloy and a 54% aluminum alloy will be needed to produce 640 pounds of the 65% aluminum alloy?\r
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Algebra.Com's Answer #39749 by ankor@dixie-net.com(22740)\"\" \"About 
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To meet the government's specifications, an alloy must be 65% aluminum. How many pounds each of a 70% aluminum alloy and a 54% aluminum alloy will be needed to produce 640 pounds of the 65% aluminum alloy?
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\n" ); document.write( "A typical mixture problem, if you learn this method you will be able to handle most mixture-type problems.
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\n" ); document.write( "Let x = the amt of the 70% alloy; Since the total will be 640 lb,
\n" ); document.write( "the 54% amt = (640-x)
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\n" ); document.write( ".70x + .54(640-x) = .65(640)
\n" ); document.write( ".70x + 345.6 -.54x = 416
\n" ); document.write( ".70x - .54x = 416 - 345.6
\n" ); document.write( ".16x = 70.4
\n" ); document.write( "x = 70.4/.16
\n" ); document.write( "x = 440 lb of 70% aluminum
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\n" ); document.write( "640 - 440 = 200 lb of the 54% aluminum
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\n" ); document.write( "Check:
\n" ); document.write( ".7(440) + .54(200) = .65(640)
\n" ); document.write( " 308 + 108 = 416
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