document.write( "Question 58109: To meet the governments specifications, an alloy must be 65% aluminum. How many pounds each of a 70% aluminum alloy and a 54% aluminum alloy will be needed to produce 640 pounds of the 65% aluminum alloy?\r
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document.write( "Any help with this one is appreciated!
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Algebra.Com's Answer #39748 by hayek(51)![]() ![]() ![]() You can put this solution on YOUR website! Amount of 70% Al: \n" ); document.write( "Amount of 54% Al: \n" ); document.write( "----------- \n" ); document.write( "The problem tells us to mix the two. \n" ); document.write( "The total amount of pure aluminum in the mix will be: (Eq. 1) \n" ); document.write( "\n" ); document.write( "The total amount of material in the mix \n" ); document.write( "\n" ); document.write( "We are looking for a final mix of 640 pounds of 65% Al. Thus, the total aluminum content of the final is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plugging that back into Eq. 1 gives: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solving Eq. 2 for \n" ); document.write( "Plug that into the previous equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Plug this into Eq. 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |