document.write( "Question 58109: To meet the governments specifications, an alloy must be 65% aluminum. How many pounds each of a 70% aluminum alloy and a 54% aluminum alloy will be needed to produce 640 pounds of the 65% aluminum alloy?\r
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Algebra.Com's Answer #39748 by hayek(51)\"\" \"About 
You can put this solution on YOUR website!
Amount of 70% Al: \"Al%5B70%5D\"
\n" ); document.write( "Amount of 54% Al: \"Al%5B54%5D\"
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\n" ); document.write( "The problem tells us to mix the two.
\n" ); document.write( "The total amount of pure aluminum in the mix will be: (Eq. 1) \"Al%5Btot%5D=Al%5B70%5D%2A%28.70%29%2BAl%5B54%5D%2A%28.54%29\" \r
\n" ); document.write( "\n" ); document.write( "The total amount of material in the mix \"Al%5B70%5D%2BAl%5B54%5D\",must equal 640 pounds ==> (Eq. 2) \"Al%5B70%5D%2BAl%5B54%5D=640\"\r
\n" ); document.write( "\n" ); document.write( "We are looking for a final mix of 640 pounds of 65% Al. Thus, the total aluminum content of the final is:
\n" ); document.write( "\"Al%5Btot%5D=640%2A.65\"
\n" ); document.write( "\"Al%5Btot%5D=416\".\r
\n" ); document.write( "\n" ); document.write( "Plugging that back into Eq. 1 gives:
\n" ); document.write( "\"416=Al%5B70%5D%2A%28.70%29%2BAl%5B54%5D%2A%28.54%29\"\r
\n" ); document.write( "\n" ); document.write( "Solving Eq. 2 for \"Al%5B70%5D\"==> \"Al%5B70%5D=640-Al%5B54%5D\"
\n" ); document.write( "Plug that into the previous equation:\r
\n" ); document.write( "\n" ); document.write( "\"416=%28640-Al%5B54%5D%29%2A.7%2BAl%5B54%5D%28.54%29\"
\n" ); document.write( "\"416=448-.7%2AAl%5B54%5D%2B.54%2AAl%5B54%5D\"
\n" ); document.write( "\"416=448-.16%2AAl%5B54%5D\"
\n" ); document.write( "\"416-448=-.16%2AAl%5B54%5D\"
\n" ); document.write( "\"Al%5B54%5D=%28416-448%29%2F-.16\"
\n" ); document.write( "\"highlight%28Al%5B54%5D=200%29\" pounds.
\n" ); document.write( "Plug this into Eq. 2: \"Al%5B70%5D=640-200\" ==> \"highlight%28Al%5B70%5D=440%29\"pounds.\r
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