document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631261>Question 631261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The smallest  of three consecutive  integers is added to twice the largest ,the result so obtained is fifteen is fifteen less than three times the middle integer .find the integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397467 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The smallest of three consecutive integers is added to twice the largest ,the result so obtained is fifteen less than three times the middle integer .find the integers<BR>\n" );
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document.write( "1st: x-1<BR>\n" );
document.write( "2nd: x<BR>\n" );
document.write( "3rd: x+1<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "2(x+1)+x-1 = 3x - 15<BR>\n" );
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document.write( "2x+2+x-1 = 3x-15<BR>\n" );
document.write( "3x +1 = 3x-15<BR>\n" );
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document.write( "That is a contradiction.<BR>\n" );
document.write( "The conditions cannot be met by any three consecutive integers.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );