document.write( "Question 631025: The side of one square is 4 in longer than that of a second square. The area of the
\n" ); document.write( "larger is 32 sq. in less than twice the area of the smaller. Find the perimeter of each
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Algebra.Com's Answer #397462 by ankor@dixie-net.com(22740)\"\" \"About 
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The side of one square is 4 in longer than that of a second square.
\n" ); document.write( " The area of the larger is 32 sq. in less than twice the area of the smaller.
\n" ); document.write( " Find the perimeter of each square.
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\n" ); document.write( "Let x = the side of the smaller square
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\n" ); document.write( "x^2 = area of the smaller square
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\n" ); document.write( "(x+4) = side of the larger square
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\n" ); document.write( "(x+4)^2 = area of the larger square
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\n" ); document.write( "\"The area of the larger is 32 sq. in less than twice the area of the smaller.\"
\n" ); document.write( "(x+4)^2 = 2x^2 - 32
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\n" ); document.write( "x^2 + 8x + 16 = 2x^2 - 32
\n" ); document.write( "0 = 2x^2 - x^2 - 8x - 32 - 16
\n" ); document.write( "A quadratic equation
\n" ); document.write( "x^2 - 8x - 48 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-12)(x+4) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "x = 12 inches the side of the smaller square
\n" ); document.write( "4(12) = 48 in, the perimeter
\n" ); document.write( "and
\n" ); document.write( "12+4 = 16 inches the side of the larger square
\n" ); document.write( "4(16) = 64 inches the perimeter\r
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