document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631210>Question 631210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you write the binomial expansion for question # 1 & 2?<BR>\n" );
document.write( "1. (2x+3)3 < - -3rd power<BR>\n" );
document.write( "2. (2x-y)6 < - - 6th power\r<BR>\n" );
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document.write( "3. What is the 3rd term of the expansion for (x+3)7 < - - 7th power<BR>\n" );
document.write( "4. What is the 5th term of the expansion for (2x-3y)5 < - - 5h power<BR>\n" );
document.write( "5. find the coefficient of x3 < - - x to the 3rd power in the expansion (x+3)5 < - 5th power </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397458 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write the binomial expansion for question # 1 & 2?<BR>\n" );
document.write( "1. (2x+3)^3 = 3C3*(2x)^3 + 3C2*(2x)^2*3 + 3C1(2x)*3^2 + 3C0*3^3<BR>\n" );
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document.write( "2. (2x-y)^6 <BR>\n" );
document.write( "Same pattern as above but starting with 6C6<BR>\n" );
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document.write( "3. What is the 3rd term of the expansion for (x+3)^7 <BR>\n" );
document.write( "Ans: 7C5(x^5)(3^2)<BR>\n" );
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document.write( "4. What is the 5th term of the expansion for (2x-3y)^5<BR>\n" );
document.write( "Ans: 5C1(2x)(-3y)^4<BR>\n" );
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document.write( "5. find the coefficient of x3  in the expansion (x+3)^5<BR>\n" );
document.write( "Ans: 5C3(x^3)*3^2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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