document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631153>Question 631153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. The round trip from home to work takes 1.5 hrs. What is the distance to work if the trip going to it was done at 7 miles per hour and the return trip at 12 miles per hour? Verify.\r<BR>\n" );
document.write( "\n" );
document.write( "______________________________________…\r<BR>\n" );
document.write( "\n" );
document.write( "2. Bob rows his boat at 50 m/min going downstream and 20 m/min going upstream. How far down the river should he go so that he can return at 3:05pm; from where he started, if he left at 10:45 am? Verify.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you can help me with these questions it'll be great! I could not find any ways to solve them. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397446 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. The round trip from home to work takes 1.5 hrs.<BR>\n" );
document.write( " What is the distance to work if the trip going to it was done at 7 miles per<BR>\n" );
document.write( " hour and the return trip at 12 miles per hour? Verify.<BR>\n" );
document.write( "let d = distance to work<BR>\n" );
document.write( "Write a time equation: time = dist/speed<BR>\n" );
document.write( ":<BR>\n" );
document.write( "to work time + return time = 1.5 hrs<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F7 ALIGN=MIDDLE  ALT=\"d%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F12 ALIGN=MIDDLE  ALT=\"d%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1.5<BR>\n" );
document.write( "multiply by 84 to get rid of the denominators<BR>\n" );
document.write( "84*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F7 ALIGN=MIDDLE  ALT=\"d%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 84*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F12 ALIGN=MIDDLE  ALT=\"d%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 84*1.5<BR>\n" );
document.write( "cancel the denominators<BR>\n" );
document.write( "12d + 7d = 126<BR>\n" );
document.write( "19d = 126<BR>\n" );
document.write( "d = 126/19<BR>\n" );
document.write( "d = 6.63 mi dist to work<BR>\n" );
document.write( ":<BR>\n" );
document.write( "verify by finding the times each way<BR>\n" );
document.write( "6.63/7 = .947 hrs<BR>\n" );
document.write( "6.63/12= .553 hrs<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "total time: 1.5 hrs<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "2. Bob rows his boat at 50 m/min going downstream and 20 m/min going upstream.<BR>\n" );
document.write( " How far down the river should he go so that he can return at 3:05pm; from <BR>\n" );
document.write( " where he started, if he left at 10:45 am? Verify.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the number of minutes from 10:45 am to 3:05 pm<BR>\n" );
document.write( "14:65 - 10:45 = 4:20;   4(60) + 20 = 260 minutes downstream and back<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let d = the one way distance downstream<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Write a time equation: time = dist/speed<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Time downstream + time back = 260 min<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F50 ALIGN=MIDDLE  ALT=\"d%2F50\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F20 ALIGN=MIDDLE  ALT=\"d%2F20\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 260<BR>\n" );
document.write( "multiply by 100 to get rid of the denominators<BR>\n" );
document.write( "2d + 5d = 260 * 100<BR>\n" );
document.write( "7d = 26000<BR>\n" );
document.write( "d = 26000/7<BR>\n" );
document.write( "d = 3,714.3 meters downstream (3.7 km)<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Verify this by finding the time each way<BR>\n" );
document.write( "3714.3/50 =  74.3 min<BR>\n" );
document.write( "3714.3/20 = 185.7 min<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "total time: 260 min<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );