document.write( "Question 631098: I have tried and tried on this problem and just cant get it right. I even had a tutor online help me and they got it wrong too... this is the problem ...\r
\n" ); document.write( "\n" ); document.write( "Solve the system of equations. Round approximate values to the nearest ten-thousandth. \r
\n" ); document.write( "\n" ); document.write( "y = log2x
\n" ); document.write( "y = x−5
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Algebra.Com's Answer #397443 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "There is no algebraic solution to this equation. You have to use numerical methods.\r
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\n" ); document.write( "\n" ); document.write( "I used a graphing program and then ran some numbers through the function in Excel. I was able to come up with two intervals: [0.000005,0.000006] and [6,6.1] where the function changes sign from one end of the interval to the other. The Intermediate value theorem says there has to be a root on each of those intervals.\r
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\n" ); document.write( "\n" ); document.write( "Then I used the Newton-Raphson method:\r
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\n" ); document.write( "\n" ); document.write( "I first defined the function as\r
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\n" ); document.write( "\n" ); document.write( "Then Newton-Raphson says \r
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\n" ); document.write( "\n" ); document.write( "and then a closer approximation can be obtained from:\r
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\n" ); document.write( "\n" ); document.write( "And you can repeat the process as often as you like to get the desired precision.\r
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\n" ); document.write( "\n" ); document.write( "The derivative of is:\r
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\n" ); document.write( "\n" ); document.write( "You can run a calculator as well as I can. Enjoy.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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