document.write( "Question 631182: Americans watch an average of 3.5 hours of television per person per day. If the standard deviation for the number of hours of television watched per day is 3.9 and a random sample of 266 Americans is selected, the mean of this sample belongs to a sampling distribution.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the shape of this sampling distribution?
\n" ); document.write( " (1)skewed right normal
\n" ); document.write( " (2)symmetrical
\n" ); document.write( " (3)skewed left
\n" ); document.write( " (4)uniform\r
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\n" ); document.write( "\n" ); document.write( "(b) What is the mean of this sampling distribution? (Give your answer correct to one decimal place.)\r
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\n" ); document.write( "\n" ); document.write( "(c) What is the standard deviation of this sampling distribution? (Give your answer correct to two decimal places.)
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Algebra.Com's Answer #397406 by jim_thompson5910(35256)\"\" \"About 
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(a) What is the shape of this sampling distribution?\r
\n" ); document.write( "\n" ); document.write( "(1)skewed right normal
\n" ); document.write( "(2)symmetrical
\n" ); document.write( "(3)skewed left
\n" ); document.write( "(4)uniform\r
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\n" ); document.write( "\n" ); document.write( "Answer choice marked in red.\r
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\n" ); document.write( "\n" ); document.write( "This is because the distribution will approach a normal distribution (ie become more like it) as you increase the sample size.
\n" ); document.write( "Remember that normal distributions are symmetrical.\r
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\n" ); document.write( "\n" ); document.write( "The other choices that involved the word \"skewed\" are incorrect because skewed is the opposite of symmetrical. So that's out. \r
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\n" ); document.write( "\n" ); document.write( "Also, it's not uniform because the more extreme cases (eg: those who watch barely any TV or those who watch too much TV) will not have the same proportion as those who watch the average amount of TV\r
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\n" ); document.write( "\n" ); document.write( "(b) What is the mean of this sampling distribution? (Give your answer correct to one decimal place.)\r
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\n" ); document.write( "\n" ); document.write( "The mean of the sampling distribution is equal to the population mean. So the mean of this sampling distribution is 3.5 hours.\r
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\n" ); document.write( "\n" ); document.write( "(c) What is the standard deviation of this sampling distribution? (Give your answer correct to two decimal places.)\r
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\n" ); document.write( "\n" ); document.write( "The standard deviation of the sampling distribution with population standard deviation \"sigma\" and size \"n\" is \r
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\n" ); document.write( "\n" ); document.write( "Plug in \"sigma+=+3.9\" and \"n+=+266\" and simplify...\r
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\n" ); document.write( "\n" ); document.write( "So the standard deviation of this sampling distribution is approximately 0.24 (rounded to two decimal places).\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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