document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=631071>Question 631071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi . could someone help me simpify the following expression<BR>\n" );
document.write( "L^2m(2-m)/L^3(m-2) many thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397325 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simpify the following expression<BR>\n" );
document.write( "L^2m(2-m)/L^3(m-2) <BR>\n" );
document.write( "-------<BR>\n" );
document.write( "= m(L^2/L^3)(2-m)/(m-2)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Since 2-m = -(m-2) , (2-m)/(m-2) = -1. <BR>\n" );
document.write( "-----<BR>\n" );
document.write( "= (m/L)(-1)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= -m/L<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );