document.write( "Question 7201: will you please help me factor this equation: 16k squared minus 80k plus 100. thankyou \n" ); document.write( "
Algebra.Com's Answer #3973 by Earlsdon(6294)\"\" \"About 
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Factor:\r
\n" ); document.write( "\n" ); document.write( "\"16k%5E2+-+80k+%2B+100\" Factor a 4 first.\r
\n" ); document.write( "\n" ); document.write( "\"4%284k%5E2+-+20k+%2B+25%29\" Now try:\r
\n" ); document.write( "\n" ); document.write( "\"4%282k+-+5%29%282k+-+5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "The reason to try a -5 constant term in the factors is because you want to get a +25 as the constant in the second equation The only way is to have (-5)(-5) in the factors. Well, (-1)(-25) also = +25 but you can quickly see that this would not work.\r
\n" ); document.write( "\n" ); document.write( "So the complete factorisation is: 4(2k-5)(2k-5) \r
\n" ); document.write( "\n" ); document.write( "Check the solution by using FOIL:\r
\n" ); document.write( "\n" ); document.write( "\"4%282k-5%29%282k-5%29+=+4%284k%5E2+-+10k+-+10k+%2B+25%29\" = \"16k%5E2+-+80k+%2B+100\"
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