document.write( "Question 631046: Sandra is 5 times as old as her son Ross. 3 years ago she was 7 times his age. How old is Ross? \n" ); document.write( "
Algebra.Com's Answer #397292 by 303795(602)\"\" \"About 
You can put this solution on YOUR website!
Now
\n" ); document.write( "Ross' age = r
\n" ); document.write( "Sandra's age = 5r
\n" ); document.write( " Three years ago
\n" ); document.write( "Ross' age = r - 3
\n" ); document.write( "Sandra's age = 5r - 3
\n" ); document.write( "Sandra was 7 times Ross' age so
\n" ); document.write( "5r - 3 = 7(r - 3)
\n" ); document.write( "5r - 3 = 7r - 21
\n" ); document.write( "Subtract 5r from each side
\n" ); document.write( "5r - 3 - 5r = 7r - 21 - 5r
\n" ); document.write( "-3 = 2r - 21
\n" ); document.write( "Add 21 to each side
\n" ); document.write( "-3 + 21 = 2r - 21 + 21
\n" ); document.write( "18 = 2r
\n" ); document.write( "r = 9
\n" ); document.write( "So Ross is currently 9 and Sandra is 45. Three years ago he was 6 and she was 42.
\n" ); document.write( "
\n" ); document.write( "
\n" );