document.write( "Question 631031: Another Quadtic Formula: Solve by FACTORING......\r
\n" ); document.write( "\n" ); document.write( "problem: 2a^^2 + 1= -3a\r
\n" ); document.write( "\n" ); document.write( "Now I worked it out But I don't know if it is right:\r
\n" ); document.write( "\n" ); document.write( "The variable is P\r
\n" ); document.write( "\n" ); document.write( "p= sq/rt-p-1 - sw/rt
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Algebra.Com's Answer #397286 by 303795(602)\"\" \"About 
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Rearrange to get one side equal to zero.
\n" ); document.write( "2a^2 + 1= -3a
\n" ); document.write( "Add 3a to each side
\n" ); document.write( "2a^2 + 1 + 3a = -3a + 3a
\n" ); document.write( "2a^2 + 3a + 1 = 0
\n" ); document.write( "Factorise the equation to get
\n" ); document.write( "(2a + 1)(a + 1) = 0
\n" ); document.write( "So either (2a + 1) = 0 or (a + 1) = 0
\n" ); document.write( "Case 1
\n" ); document.write( "2a + 1 = 0
\n" ); document.write( "2a = -1
\n" ); document.write( "a = -1/2
\n" ); document.write( "Case 2
\n" ); document.write( "a + 1 = 0
\n" ); document.write( "a = -1
\n" ); document.write( "So a is either -1 or -0.5
\n" ); document.write( "I have no idea what the P part of your problem has to do with this solution.
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