document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630992>Question 630992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a 15% silver alloy and a 30% silver alloy. How much of each alloy is need to be mixed to obtain 25 kg of an alloy that is 20% silver? (show work) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397283 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A chemist has a 15% silver alloy and a 30% silver alloy. How much of each alloy is need to be mixed to obtain 25 kg of an alloy that is 20% silver? (show work)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = amount (kg) of 15% silver<BR>\n" );
document.write( "then<BR>\n" );
document.write( "25-x = amount (kg) of 30% silver<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".15x + .30(25-x) = .20(25)<BR>\n" );
document.write( ".15x + 7.5-.30x = 5<BR>\n" );
document.write( "7.5-.15x = 5<BR>\n" );
document.write( "-.15x = -2.5<BR>\n" );
document.write( "x = -2.5/(-.15)<BR>\n" );
document.write( "x = 2.5/(.15)<BR>\n" );
document.write( "x = 250/15<BR>\n" );
document.write( "x = 50/3<BR>\n" );
document.write( "x = 16.67 kg (15% silver)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "30% silver:<BR>\n" );
document.write( "25-x = 25-16.67 = 8.33 kg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );