document.write( "Question 58055: A piece of wire 10m long is cut into two pieces one piece is bent into a square and the other is bent into a circle. Express the total area A of the square and circle as a function of x, th elength of the sides of the square. how should the wire be cut so that the total area enclosed is a minimum? what is the total enclosed area? \n" ); document.write( "
Algebra.Com's Answer #39727 by stanbon(75887)\"\" \"About 
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A piece of wire 10m long is cut into two pieces one piece is bent into a square and the other is bent into a circle. Express the total area A of the square and circle as a function of x, th elength of the sides of the square. how should the wire be cut so that the total area enclosed is a minimum? what is the total enclosed area?
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\n" ); document.write( "One piece is \"x\" m long; the other is \"10-x\" m long.
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\n" ); document.write( "Using x to make the square,
\n" ); document.write( "each side is x/4 m,
\n" ); document.write( "and the area is (x/4)^2=x^2/16 m^2\r
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\n" ); document.write( "Using 10-x to make the circle,
\n" ); document.write( "circumference = 2(pi)r=10-x
\n" ); document.write( "r=(10-x)/2pi
\n" ); document.write( "and area is pi[(10-x)/2pi)^2= (4/pi)(10-x)^2
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\n" ); document.write( "Total area = (x^2/16)+(4/pi)(10-x)^2
\n" ); document.write( "Mimumum at 9.53... using a TI-83 calculator
\n" ); document.write( "Area when x=9.53... is 5.9576 m^2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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