document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630984>Question 630984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular field is 276 m. the length is 18 m longer than the width. what are the dimensions of the field? (show work) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397254 by </B><A HREF=/tutors/aboutme.mpl?userid=Taino><B>Taino(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Taino><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given: A rectangular field  \r<BR>\n" );
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document.write( "Length of the field is 18 m longer than the width (L = W + 18)\r<BR>\n" );
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document.write( "Perimeter (P) = 276 m\r<BR>\n" );
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document.write( "Determine: The dimensions of the field.\r<BR>\n" );
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document.write( "Equation: P = 2*L + 2*W ----> 2*(W + 18) + 2*W ----> 2*w + 36 + 2*W\r<BR>\n" );
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document.write( "          P = 4*W + 36 = 276 ----> 4*W = 276 - 36 ----> W = 240 / 4 = 60m\r<BR>\n" );
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document.write( "                                                        W = 60 m\r<BR>\n" );
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document.write( "          L = W + 18 = 60 + 18 = 78m\r<BR>\n" );
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document.write( "Therefore the dimensions of the field are: W = 60 m  and L = 78 m<BR>\n" );
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