document.write( "Question 630687: find the volume of the bounded area of y=x^2 and y=2-x^2 about x=2 \n" ); document.write( "
Algebra.Com's Answer #397165 by Alan3354(69443) You can put this solution on YOUR website! find the volume of the bounded area of y=x^2 and y=2-x^2 about x=2 \n" ); document.write( "----------------- \n" ); document.write( "Find the area under y = 2-x^2 and above the x-axis: \n" ); document.write( "INT = 2x - x^3/3 \n" ); document.write( "Evaluate from -1 to 1 \n" ); document.write( "@1 --> 2 - 1/3 \n" ); document.write( "@-1 --> -2 + 1/3 \n" ); document.write( "-------------- Subtract \n" ); document.write( "Area = 4 -2/3 = 10/3 \n" ); document.write( "====================== \n" ); document.write( "From that, subtract the area under y = x^2 from -1 to +1 [-1 and +1 are the intersections of the 2 curves] \n" ); document.write( "---------- \n" ); document.write( "INT = x^3/3 \n" ); document.write( "Area = 1/3 - (-1/3) = 2/3 \n" ); document.write( "======================== \n" ); document.write( "Area between curves = 8/3 sq units \n" ); document.write( "The 2 curves are symmetrical, so the centroid of the area is (0,1) \n" ); document.write( "Use the Theorem of Pappus to find the volume: \n" ); document.write( "Vol = 2pi*distance to centroid*area \n" ); document.write( "Vol = 2pi*2*8/3 cubic units \n" ); document.write( "Vol = 32pi/3 cubic units \n" ); document.write( "=~ 33.51 CU \n" ); document.write( " |