document.write( "Question 630761: The age of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one.what is their present age? \n" ); document.write( "
Algebra.Com's Answer #397162 by dfrazzetto(283)![]() ![]() You can put this solution on YOUR website! e = elder\r \n" ); document.write( "\n" ); document.write( "y = younger\r \n" ); document.write( "\n" ); document.write( "e - y = 20\r \n" ); document.write( "\n" ); document.write( "e = 20 + y\r \n" ); document.write( "\n" ); document.write( "e - 5 = 5(y-5)\r \n" ); document.write( "\n" ); document.write( "20 + y - 5 = 5y - 25\r \n" ); document.write( "\n" ); document.write( "y + 15 = 5y - 25\r \n" ); document.write( "\n" ); document.write( "4y = 40\r \n" ); document.write( "\n" ); document.write( "y = 10\r \n" ); document.write( "\n" ); document.write( "e = 30\r \n" ); document.write( "\n" ); document.write( "CHECK:\r \n" ); document.write( "\n" ); document.write( "30 - 5 = 5(10-5)\r \n" ); document.write( "\n" ); document.write( "25 = 5*5= 25\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |