document.write( "Question 630723: Suppose that you are on a salvage ship in the Gulf of Mexico. Your sonar system has located a sunken Spanish galleon at a slant distance of 68.3 meters from your ship, with an angle of depression of 27°52′.
\n" ); document.write( " a) How deep is the water at the galleon’s location?
\n" ); document.write( " b) How far must you sail to be directly above the galleon?
\n" ); document.write( " c) You sail directly toward the spot over the galleon. When you have gone 520 meters, what should the angle of depression be?\r
\n" ); document.write( "\n" ); document.write( "i'm stuck with c. i got b, x=603.8m, then in c it says 520m, which is smaller than 604.8cm? how is it possible? or i have wrong interpretation?\r
\n" ); document.write( "\n" ); document.write( "pls. help!!
\n" ); document.write( "

Algebra.Com's Answer #397096 by rmnavalta(7)\"\" \"About 
You can put this solution on YOUR website!
I've corrected the given from 68.3 to 683meters.
\r
\n" ); document.write( "\n" ); document.write( "For the illustration please see this (placed on my fb profile)
\n" ); document.write( "https://www.facebook.com/photo.php?fbid=3633779889920&set=a.1100830367765.2014805.1436862519&type=1&relevant_count=1&ref=nf\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Solution:\r\n" );
document.write( "(a) Let d = depth of water @ galleon's location\r\n" );
document.write( " Use sine of angle of depression = opposite / hypotenuse.\r\n" );
document.write( " 

\n" ); document.write( " sin 27°52′=d/683
\n" ); document.write( " d = 683sin 27°52′ ---> Multiply both sides by 683.
\n" ); document.write( " d = 319.24 meters --->Ans. depth of water @ galleon's location
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b) Let x = distance the ship would sail to be directly above the galleon\r\n" );
document.write( " Use cosine of angle of depression = adjacent / hypotenuse.\r\n" );
document.write( " 

\n" ); document.write( "cos 27°52′=d/683
\n" ); document.write( " x = 683cos 27°52′ ---> Multiply both sides by 683.
\n" ); document.write( " x = 603.8 meters --->Ans. distance the ship would sail to be directly above the galleon
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b) Let angle B = angle of depression of the galleon when the ship has gone 520 m\r\n" );
document.write( " Use tangent of angle of depression(angle B) = opposite / adjacent.\r\n" );
document.write( "  

\n" ); document.write( "tan (angle B) = d/x-520
\n" ); document.write( "tan (angle B) = 319.24/(603.8-520)     ---> Solved from (a)d=319.24 and (b)x=603.8
\n" ); document.write( "(angle B) = arctan (319.24/83.8)     ---> Get arctan of both sides.\r
\n" ); document.write( "\n" ); document.write( "(angle B) = 75.29° or 75°17′   ---> Ans. angle of depression of the galleon when the ship has gone 520 m
\n" ); document.write( "

\n" ); document.write( "Answers;
\n" ); document.write( "(a) depth of water @ galleon's location = 319.24 meters
\n" ); document.write( "(b) distance the ship would sail to be directly above the galleon = 603.8 meters
\n" ); document.write( "(c) angle of depression of the galleon when the ship has gone 520 m= 75.29° or 75°17′
\n" ); document.write( "God bless. Email me- rmnavalta@yahoo.com
\n" ); document.write( "
\n" );