document.write( "Question 630728: Jamie is twice as old as her brother.Four years ago,she was 4 times as old as her brother.Find their ages now.
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Algebra.Com's Answer #397094 by rmnavalta(7) $\"\"$ $\"About$

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document.write( "Let x = age of Jamie's brother\r\n" );
document.write( "   2x = Jamie's age               ***Jamie is twice as old as her brother\r\n" );
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document.write( "Let's use a table.\r\n" );
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document.write( "             |   Age NOW  |  Age 4 YEARS AGO |\r\n" );
document.write( "Jamie        |      2x    |      2x-4        |\r\n" );
document.write( "Her Brother  |      x     |      x-4         |\r\n" );
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document.write( "Four years ago, she (Jamie) was(is equal to) 4 times as old as her brother.\r\n" );
document.write( "                    2x-4          =             4 times (x-4)\r\n" );
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document.write( "Set-up the equation.   2x-4 = 4(x-4)\r\n" );
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document.write( "Solve.         2x-4 = 4x-16       -->Simplify 4(x-4).\r\n" );
document.write( "           2x-4 -4x = 4x-16 -4x   -->Subtract 4x on both sides.\r\n" );
document.write( "           -2x-4 +4 = -16 +4      -->Add 4 on both sides.\r\n" );
document.write( "         (-2x)/(-2) = (-12)/(-2)  -->Divide both sides by -2.\r\n" );
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document.write( "                  x = 6 years (age of Jamie's brother\r\n" );
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document.write( "Jamie's age = 2x = 2(6) = 12 years\r\n" );
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document.write( "Answer: Jamie is 12 years old and her brother is 6 years old.\r\n" );
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