document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=630726>Question 630726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first number is four more than two times the second number. The sum of the two numbers is ninety-seven. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #397092 by </B><A HREF=/tutors/aboutme.mpl?userid=rmnavalta><B>rmnavalta(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rmnavalta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rmnavalta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=397092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the first number<BR>\n" );
document.write( "   97-x= the second number \r<BR>\n" );
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document.write( "The first number x is equal to 2 times the second number + 4, so the equation is\r<BR>\n" );
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document.write( "x=2(97-x)+4\r<BR>\n" );
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document.write( "x=194-2x+4       -- multiply 2 and (97-x), applying distributive property<BR>\n" );
document.write( "x+2x=194-2x+4+2x --add 2x on both sides of the eqn<BR>\n" );
document.write( "3x = 198         -- 194+4=198<BR>\n" );
document.write( "(3x)/3 = 198/3   -- Divide both sides by 3\r<BR>\n" );
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document.write( "x=66       -------> the value of the first number<BR>\n" );
document.write( "second number = 97-x<BR>\n" );
document.write( "              = 97-66<BR>\n" );
document.write( "              = 31\r<BR>\n" );
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document.write( "Answer: The two numbers are 66 and 31.<BR>\n" );
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