document.write( "Question 630643: 1/B = 1/s + 1/t solve for t ????????????? \n" ); document.write( "
Algebra.Com's Answer #397074 by Edwin McCravy(20055)\"\" \"About 
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document.write( "The other tutor did not simplify the answer, but left\r\n" );
document.write( "fractions within a fraction.\r\n" );
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document.write( "\"1%2FB\" = \"1%2Fs\" +\"1%2Ft\"\r\n" );
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document.write( "Since none of the denominators have any common factors, the LCD\r\n" );
document.write( "is just their product B·s·t.  Write that as \"B%2As%2At%2F1\" and multiply\r\n" );
document.write( "every term by that\r\n" );
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document.write( "\"1%2FB\"·\"B%2As%2At%2F1\" = \"1%2Fs\"·\"B%2As%2At%2F1\" +\"1%2Ft\"·\"B%2As%2At%2F1\"\r\n" );
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document.write( "Cancel:\r\n" );
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document.write( "\"1%2Fcross%28B%29\"·\"cross%28B%29%2As%2At%2F1\" = \"1%2Fcross%28s%29\"·\"B%2Across%28s%29%2At%2F1\" +\"1%2Fcross%28t%29\"·\"B%2As%2Across%28t%29%2F1\"\r\n" );
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document.write( "s·t = B·t + B·s\r\n" );
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document.write( "Get the terms that has t alone on one side.  So we subtract B·t\r\n" );
document.write( "from both sides\r\n" );
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document.write( "s·t - B·t = B·s\r\n" );
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document.write( "Next we factor out t on the left side\r\n" );
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document.write( "t·(s - B) = B·s\r\n" );
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document.write( "Now we divide both sides by (s - B)\r\n" );
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document.write( "\"t%2A%28s+-+B%29%2F%28s+-+B%29\" = \"B%2As%2F%28s-b%29\"\r\n" );
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document.write( "Cancel the (s - B)'s on the left side:\r\n" );
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document.write( "t = \"B%2As%2F%28s-B%29\"\r\n" );
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document.write( "Edwin
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