document.write( "Question 630623: How many different ways can 4 women and 7 men be selected from
\n" ); document.write( "11 married couples (assuming no gay marriages). \n" ); document.write( "
Algebra.Com's Answer #397068 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\"11 women choose 4\", that's C(11,4) or 330.\r\n" );
document.write( "\r\n" );
document.write( "For each of those 330 ways to choose the 4 women, there are\r\n" );
document.write( "\r\n" );
document.write( "\"11 men choose 7\", that's C(11,7) or 330 ways to choose the men.\r\n" );
document.write( "\r\n" );
document.write( "Therefore the answer is C(11,4)·C(11,7) = 330·330 = 108,900 ways.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );