document.write( "Question 630612: 6x+8y=60
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document.write( "7x+6y=60
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document.write( "6x+8y=7x+6y \n" );
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Algebra.Com's Answer #397051 by 55305(86)![]() ![]() ![]() You can put this solution on YOUR website! First lets find out how many y's are in an x. So if we subtract 6x and 6y from each side of the equation 6x+8y=7x+6y, we get 2y=x. So if we put 2y in for every x in 6x+8y=60, then we get 12y+8y=60, which is the same as 20y=60. So if we divide that by 20, we get y=3. So if we put y=3 into any equation, suppose 7x+6y=60, which is the same as 7x+18=60, and then we subtract 18 from each side, and then divide by 7, \n" ); document.write( "7x=42 \n" ); document.write( "x=6 \n" ); document.write( "we get x=6. So y=3 and x=6. \n" ); document.write( " |