document.write( "Question 630604: \"++%28log%28%28z%29%29%29%5E2=log%28%28z%5E2%29%29++\" \n" ); document.write( "
Algebra.Com's Answer #397039 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(log((z)))^2=log((z^2))
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\n" ); document.write( "= [log(z)]^2 - 2log(z) = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "log(z)[log(z)-2)] = 0
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\n" ); document.write( "log(z) = 0 or log(z) = 2
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\n" ); document.write( "z = 1 or z = 100
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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